FUNCTION TEMPLATE USING C++

/*PROGRAM USING FUNCTION TEMPLATE*/

PROGRAM

#include<iostream.h>

#include<conio.h>

template<class T>T sum(T *array,int n)

{

T temp=0;

for(int i=0;i<=n-1;i++)

temp=temp+array[i];

return(temp);

}

int sum(int *a,int n);

float sum(float *b,int n);

double sum(double *c,int n);

long int sum(long int *d,int n);

short int sum(short int *e,int n);

void main()

{

clrscr();

int n=3,sum1;

float sum2;

double sum3;

long int sum4;

short int sum5;

static int a[3]={1,2,3};

static float b[3]={1.1,2.2,3.3};

static double c[3]={43.33,32.86,56.33};

static long int d[3]={555,655,755};

static short int e[3]={5,5,5};

cout<<"\n\t\t PROGRAM USING FUNCTION TEMPLATE";

cout<<"\n\t\t _______________________________\n";

sum1=sum(a,n);

cout<<"\n Sum of the integers="<<sum1<<endl;

sum2=sum(b,n);

cout<<"\n Sum of float is="<<sum2<<endl;

sum3=sum(c,n);

cout<<"\n Sum of double ="<<sum3<<endl;

sum4=sum(d,n);

cout<<"\n Sum of long int ="<<sum4<<endl;

sum5=sum(e,n);

cout<<"\n Sum of short int ="<<sum5<<endl;

getch();

}

OUTPUT:

                 PROGRAM USING FUNCTION TEMPLATE

                 _______________________________________

 Sum of the integers=6

 Sum of float is=6.6

 Sum of double =132.52

 Sum of long int =1965

 Sum of short int =15