OPERATING SYSTM’s ALGORITHM (In LINUX OS) - PRODUCER CONSUMER PROBLEM



PRODUCER CONSUMER PROBLEM



PROGRAM:

#include<stdio.h>
#include<string.h>
main()
{
int i,size,count=0,c,x=1,no,h,buf[100];
printf(“\nEnter the buffer size”);
scanf(“%d”,&size);
do
{
printf(“\n1.Produce\n2.Consume\n3.View produced item\n4.Exit”);
printf(“\nEnter your choice”);
scanf(“%d”,&c);
switch(c)
{
            case 1:
                        if(count>=size)
                                    printf(“\nBuffer is full”);
                        else
                        {
                        printf(“\nEnter the number of elements to be produced”);
                                    scanf(“%d”,&no);
                                    if((count+no)>size)
                                                printf(“\nEnter the number less than %d”,(size-count+1));
else
{
h=count;
for(i=++h;i<=(h+no-1);i++)
{
            printf(“\nEnter the value”);
            scanf(“%d”,&buf[i]);
            count++;
}
                                                            }
                                                }
                                    case 2:
                                                if(count==0)
                                                            printf(“\nBuffer  is empty”);
                                                else
                                                {
                                                            for(i=1;i<=count;i++)
                                                                        buf[i]=buf[i+1];
                                                            count--;
                                                }
                                                break;
                                    case 3:
                                                for(i=1;i<=count;i++)
                                                            printf(“\n%d”,buf[i]);
                                                printf(“\nNumber of items in the buffer = %d”,count);
                                                break;
                                    }
                                    printf(“\nTo continue press 1 else press 0”);
                                    scanf(“%d”,&x);
                        }while(c!=4);
            }

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